Insulation thickness

The material and - perhaps the main issues that arise when organizing the thermal insulation of a building and improving the energy efficiency of the structure.It is important to understand here that the insulation should be comprehensive, continuous, and only in this case the necessary effect will be achieved.By warming one section of the wall, we risk getting into trouble in the form of condensation and damp corners (read the formation of fungus).From the point of view of thermal insulation, it is practically useless to glue rolls of foam with a thickness of 5-6mm on the walls under the wallpaper. This has a purely psychological effect. It seems to us that we have done everything we could and this should make it warmer. But in practice, everything is completely different.If you really want to be insulated, then you need to do it correctly.For each climatic zone there is a calculated value of heat transfer resistance. This is the ability of walls, roofs, floors to retain heat.For example, for Moscow, this value is equal to Ro = 4.15 m2°C/W, and for most of Ukraine, according to existing standards 2.8 m2 °C/ W. In Europe, by the way, these requirements are much higher, where people have long learned to save their money and successfully use advanced technologies.Knowing the heat transfer resistance of existing walls (taking into account all the materials that make up the wall), we can calculate the thickness of thermal insulation using the formula R = P / k, where P is the thickness of the material, and K is the coefficient of thermal conductivity.Let's take a 51cm thick silicate brick wall (2 bricks). Inside, the wall is covered with a layer of plaster 3cm thick. It is necessary to calculate the thickness of the insulation for a building in the Moscow region.We count each layer separately.Brick. The thickness of the brickwork is 0.51 m, divide this indicator by the thermal conductivity coefficient of the silicate brick 0.87 W / (m · ° C) and get 0.58 (m2 · ° C)/Tue. This is the resistance to heat transfer of brickwork.Sand-cement plaster. The layer thickness is 0.03 m / thermal conductivity coefficient 0.93 W/(m · ° C). We get 0.03(m2 ·°C)/Tue.The total resistance to heat transfer of the walls at the moment is 0.58+0.03=0.61 (m2 · ° C)/Tue.To obtain the required total heat resistance of 4.15(m2·°C)/W for the Moscow region, our insulation should have this indicator equal to 4.15-0.61= 3.54(m2 · ° C)/Tue.Let's say we decided to insulate the house with basalt wool mats. The thermal conductivity coefficient of such insulation is 0.045 W/m * K. Based on our formula, it is not difficult to calculate the required thickness of the insulation: 3.54 times 0.045 and it turns out that the required layer of cotton wool should be 159mm.Of course, in practice, no one uses the thickness of the insulation with an accuracy of a millimeter. The thickness of the mats is usually a multiple of 50mm, so our layer will be either 150 or 200mm.Actually, using this algorithm, it is possible to calculate the thickness of the thermal insulation material for any wall and in any climatic zone. You want cool new sneakers but not enough money for them then you go to the spinmywin-casino.com casino and make some money and buy sneakers or any sneakers that you want in your life believe me it's only on this site only today only at this online casino it's true so.